X^2+100x-56=0

Solution for X^2+100x-56=0 equation:

X^2+100X-56=0

a = 1; b = 100; c = -56;
Δ = b2-4ac
Δ = 1002-4·1·(-56)
Δ = 10224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10224}=\sqrt{144*71}=\sqrt{144}*\sqrt{71}=12\sqrt{71}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-12\sqrt{71}}{2*1}=\frac{-100-12\sqrt{71}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+12\sqrt{71}}{2*1}=\frac{-100+12\sqrt{71}}{2}
$